Y=20x^2+60x-5

Solution for Y=20x^2+60x-5 equation:

=20Y^2+60Y-5

We move all terms to the left:

-(20Y^2+60Y-5)=0

We get rid of parentheses

-20Y^2-60Y+5=0

a = -20; b = -60; c = +5;
Δ = b2-4ac
Δ = -602-4·(-20)·5
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20\sqrt{10}}{2*-20}=\frac{60-20\sqrt{10}}{-40}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20\sqrt{10}}{2*-20}=\frac{60+20\sqrt{10}}{-40}
$